help me this code gives runtime NZEC error.

Question

#include <iostream>
#include<vector>

using namespace std;

int main() {
int n,q,l,m,o,sum;
cin >>n;
cin>>q;
vector <int>v(n,0);
for(int i=0;i<n;i++)
{
cin>>v[i];
}
for(int i=0;i<q;i++)
{ cin>>l>>m>>o;
if(l==1&&m<n)
{
v[m]=o;
}
if(l==2&&m<n&&o<n)
{ sum=0;
for(int j=m;j<=n;j++)
{
sum=sum+v[j];
}
cout<<sum<<endl;
}
else//if i remove this else statement it works fine otherwise it gives runtime error NZEC
return -1;

}
}

Answer 1

With fix
https://code.sololearn.com/cM5Dj7zFFo1K

Answer 2

Your input line of '1 0 3' for l m o in first set of values goes to the return statement. You are missing an else. Make:
if(l==2&&m<n&&o<n)
this:
else if(l==2&&m<n&&o<n)
Therefore, that set is processed by:
if(l==1&&m<n)
only and not the return afterwards.

Answer 3

Need to know your inputs to help fully. Your statement of removing the else, does that include the return? Where are you running it? A return of non-zero on some systems will cause an error message.

Answer 4

What inputs did you use? Did you remove the return statement?

Answer 5

oh yes ,thank u sir for helping me

Answer 6

sir I am running on online website.
and I realise that outer for loop is running only once but in input there are more number that causes that error.if I am wrong correct me.

Answer 7

input
5
5
2
3
4
8
9
1
0
3
2
0
1
2
0
4
1
2
5
2
0
3

Answer 8

yes sir I have to remove else statement.