arrays

Question

What is the output of this code?
int result = 0;
for (int i = 0; i < 5; i++) {
if (i == 3) {
result += 10;
} else {
result += i;
}
}
System.out.println(result);

i dont understand the answer
the answer is 17??

Answer 1

+= adds the current value to any existing values

so say result equals 3 and int i = 3 once it reaches the if statment result += 10 would mean that result would now equal 13 next loop would make int i equal 4 += this to result gets you 17

Answer 2

It's a for lop that adds to result based on the value of i.
When i=0:
i == 3 is false so it executes results += i;
Thus results = 0 + i==> results += 0 + 0==> results = 0.
When i=1:
i == 3 is false so it executes results += i;
Thus results = 0 + i==> results += 0 + 1==> results = 1.
When i=2:
i == 3 is false so it executes results += i;
Thus results = 1 + i==> results += 1 + 2==> results = 3.
When i=3:
i == 3 is true so it executes results += 10;
Thus results = 3 + 10==> results = 13.
When i=4:
i == 3 is false so it executes results += i;
Thus results = 13 + i==> results += 13 + 4==> results = 17.

The for loop ends here because when i = 5, the condition (i < 5) returns false and hence the loop ends.

Answer 3

1.first step i=0; 0<5 is true
so it skips if statement since i is 0
now result =result+0=0
2. i = 1; 1<5 else statement is executed result =0+1 = 1
3. i = 2; 2< 5 so else statement is executed . result = 1+2 =3
4.i = 3; 3<5 here if statement (i==3) is executed ie. result = 3+ 10 so 13
5.next i value is 4 so 4 is added result =17
next i vlaue is 5 but condition is not satisfied i< 5 so it comes out of loop and prints result as 17 ..hope u understood

Answer 4

result gets added by i in every iteration, except for i==3, where it gets added by 10

i=0: 0 (0+0)
i=1: 1 (0+1)
i=2: 3 (1+2)
i=3: 13 (3+10)
i=4: 17 (13+4)
i=5: loop condition is wrong, loop terminates

Answer 5

iteration 1: i = 0, result = 0
iteration 2: i = 1, result = 1
iteration 3: i = 2, result = 3
iteration 4: i = 3, result = 13
iteration 5: i = 4, result = 17