runtime error due to timeout

Question

import java.util.*;
import java.io.*;

class series{
public static void main(String []args){
Scanner in = new Scanner(System.in);
System.out.println("");
int q=in.nextInt();
double sum;
int a=0,b=0,n=0;
int i,j,k;
for(int p=0;p<q;p++){
a = in.nextInt();
b = in.nextInt();
n = in.nextInt();
}
in.close();
for(i=1;i<=q;i++)
{
for(j=1;j<=n-1;j++)
{
sum = 0.0;
for(k=1;k<=j;j++)
{
sum = sum + ((Math.pow(2,k-1))*b);
}
System.out.println(a + sum);
}
System.out.println();
}}}

Answer 1

You got two problems. I fixed one of them.
https://code.sololearn.com/cDfJIwpb62h5

Your inner most loop was incrementing j instead of k. (CHANGED)

Your reading a, b, & n and overwriting them, until you enter the last set.

Answer 2

required series

( a+2^0.b) , (a+2^0.b +2^1.b) , (a+2^0.b +2^1.b +2^2.b),.......(a+2^0.b +2^1.b.....2^(n-i).b)

Input Format

The first line contains an integer,q , denoting the number of queries.
Each line i of the q subsequent lines contains three space-separated integers describing the respective a,b,n values for that query.

Sample Input

2
0 2 10
5 3 5

Sample Output

2 6 14 30 62 126 254 510 1022 2046
8 14 26 50 98