Can anyone please explain this code..

Question

def f(a):
j=range(1,a+1)
b=eval("**".join([str(i)for i in j]))
return b
print(f(3))

output is 1 how??

Answer 1

Hello!
This code just power 1 in range a+1. So it doesn't matter which a you input it will be 1 anyway.
Hope it helps you.

Answer 2

def f(a):
j = range(1, a+1) # for a = 3, j = [1, 2, 3]
b = eval("**".join([str(i) for i in j])) # results in b = eval('1**2**3') which is 1
return b # b will be 1 for any parameter

Answer 3

thank you

Answer 4

j=(1,2,3)
b=eval('1**2**3')
b=1**2**3 (pow(2,3))(1 raise to the power 2 raise to the power 3)
b=1**8
b=1