Does the value of y change to 4 everywhere in the code after cout<<--y?

Question

#include <iostream>
using namespace std;

int main() {
int x=4;
int y=++x;
x=y+x;
cout <<--y;
return 0;
}

Answer 1

Yes, because you use a pre decrement operator and the priority of this operator is highest.. so y will become 4 before printing it's value.

Answer 2

Since you use a pre-decrement operator on 'y' then value of 'y' is decreased to 4 just before it is printed. And after the 'cout --y;' the 'y' value became 4, so there ...

Hth, cmiiw