How can i stop this function?

Question

https://code.sololearn.com/WhScSRUmCFdv/?ref=app

I already tried to use this:
If(n1 == 4 && n2 == 5 && n3 == 6){
break;
}
but in console shows: illegal break statemant.

this code shows all possibilities between 1 and 6 using only 3 numbers, but i need It to stop in 4 5 6.

sorry my English is very poor

Answer 1

Here is solution from what I think ur trying to do

https://code.sololearn.com/WHLDOl2BkKem/?ref=app

Answer 2

"break;" only work for loop. Use "return;" for function instead.

Edit: if you want to stop the execution of the interval and not the function only, use clearInterval() as in YUGABDH's answer

Answer 3

There are 20 possibilities, but i cant use combinations like 321 because to my porpose it is the same of 123. have you ever heard about "Megasena"?
in my country we use this formula:
P = t!/(n!*(t-n)!)
where P = possibilities
t = total of numbers
n = numbers i can use

with this formula I find how many combinations i can make

Answer 4

It cant repeat the number and i need it in order. I cant use 645 or 436 for exemple

Answer 5

thanks for helping me YUGABDH PASHTE

Answer 6

Why 111 is not possible combination and some more like this