it's supposed to be b[2] is 62 right?

Question

why in this question put as 42?
Please check this:
https://code.sololearn.com/cpS1KRi9Z79w/?ref=app

Answer 1

Tharsyini

In the first place, the provided array has been initialized with a definitive set of integers as

int b[5] = {11, 45, 62, 70, 88};

This particular array consists of 5 elements with an index-value relation as

b[0] = 11
b[1] = 45
b[2] = 62
b[3] = 70
b[4] = 88

Later on, each and every of the element can be changed as S. C. demonstrated it in his code (since it's not a const array). So, chances are the b[2]'s value gets manipulated somewhere in the code and became 42 through a direct assignment or loop or something else as

b[2] = 42;

Answer 2

Please elaborate on your question to receive helpful answers.

Answer 3

Lazzy_aplye
I didn't even say a word about programming here 🤣
Please keep the thread on topic, if you want to chat, move to Discord or use a code comment. Thanks a lot.

Answer 4

which question?

Remember, array indices start counting from 0. Although I don't know which question, that is a common mistake among beginners.

Answer 5

b [2] changes the value of the third element to 42! It doesn't retrieve the third element.

Answer 6

forgive me because I don't anything about c+ + but check this

https://code.sololearn.com/cpS1KRi9Z79w/?ref=app

Answer 7

https://www.sololearn.com/learn/CPlusPlus/1625/

Answer 8

In the Accessing Array Elements..
in the given example, the b[2] should be 62 right? because its in the 2nd counting..

Answer 9

Kindly please explain me how it will change? to 42

Answer 10

ok