Check for fisher number!

Question

What is wrong with my code? (I have written in C!)

#include <stdio.h>
#include <stdlib.h>

int main()
{
int i,mult,n;
printf("Enter the number to check for fisher: ");
scanf("%d",&n);
i=1;
while(n>=i)
{
if(n%i==0)
mult*=i;

i++;
}

if((n*n*n)==mult)
{
printf("Fisher\n");
}
else
printf("Not fisher\n");
return 0;
}

Answer 1

You didn't initialize mult. You will get garbage cause of that.

Also add curly braces to the last else statement.

Answer 2

What error msg are you getting?

Answer 3

it worked....by mistake i initialised mult to 0 instead of 1

Answer 4

If you get the answers mark it. Its easier for others to see if questions are answered or not.
And welcome😁

Answer 5

I initialized mult=1 and added curly braces to the last else....still not working

Answer 6

Thanks :D

Answer 7

what should I mark?

Answer 8

Marked it...Thanks again :D