Why compiler in C++ ignores first backslash (\) in output ?

Question

The code cout<<"\abc";
//output is abc

The code cout <<"\\pqr"
//output is \pqr

The code cout <<"\ijk\+"
//output is ijk+

Why this happens?

It ignores the appearing of a single backslash (\) at any line in a output.

Can I get a solution to this

Answer 1

backslash is used to escape some special characters that have special meanings to the compiler like ", &, ? etc. to use these characters in output we have to use the backslash, then compiler ignores character that is follwed by backslash \

e.g
cout<<"hi my name is rk & i am a developer ";

this statement will produce compilation error.

corrected code:
cout<<" hi my name is rk \& i am a developer";

Answer 2

Thanks a lot for the answer