I think I just broke Java...

Question

public class Numbers
{
public static void main(String[] args) {
int ten = 10;
int five = 5;
int result = 0;
sum(ten, five, result);
difference(ten, five, result);
}
public static void sum(int five, int ten, int addMainVars ) {

addMainVars = ten + five;

System.out.println("10 + 5 is " + addMainVars + ".");
}
public static void difference(int five, int ten, int subtractMainVars ) {

subtractMainVars = ten - five;

System.out.println("10 - 5 is " + subtractMainVars + ".");
}
}
Pay attention to method difference(). The System.out.println is supposed to display "10 - 5 is 5." Instead, it writes "10 - 5 is -5." However, when I assign variable subtractMainVars a value of "five - ten," the System.out.println displays "10 - 5 is 5." This is what I want displayed, but I need to have subtractMainVars assigned "ten - five." Please help. Thank you.

Answer 1

Darn it! you nailed me good XD

Answer 2

No you didn't, you just passed the arguments in wrong order, see, your call to difference method in main goes like this:

difference(ten, five, result);

But, definition for difference method is:

public static void difference(int five, int ten, int subtractMainVars)
{

subtractMainVars = ten - five;
// more codes here ...

Here 'five' = 10, and 'ten' = 5 (see your method call in main). So, what happened here actually is, you are doing 5 - 10, which yields -5.

Solution: Either swap the order of the 'five' and 'ten' parameters in difference method, or, don't change it, but swap ten and five in difference call in main.

Hth, cmiiw

Answer 3

Thank you very much. This helps a lot. I didn't actually feel that I broke Java, it was just click-bait. I appreciate the help!