Explain the output of the code?

Question

#include <iostream>

using namespace std;

int main ()

{

int x, y;

x = 5;

y = ++x * ++x;

cout << x << y;

x = 5;

y = x++ * ++x;

cout << x << y;

return 0;

}

Answer 1

IN PREFIX ++x FIRST x IS INCREMENTED AND THAN EVALUATION TAKE PLACE.

IN POSTFIX x++ FIRST EVALUATION IS DONE AND THAN ITS VALUE IS INCREMENTED.

Decrement goes same way.

Small example

x = x + x++ + ++x + x
=4
+ 4(post increment now x=5)
+ 6(pre increment)
+ 6.
=20.

Hope this will help you understand your code☺️☺️.