Help here !please...when I entered wrong number its ask input and then execute else statement .I want it earlier.

Question

def calculate():
aman = input("Press 1 to Add. ")

a= int(input("enter first number "))
b= int(input("enter sceond number "))
calculate()

if aman=="1":
print(a+b)
else:
print("DONT ENTER WRONG NUMBER please press 1")

again()
def again():
calc_again = input("""do you try again
please press Y for yes and N for no"")
if calc_again.upper()== 'Y':
calculate()
elif calc_again.upper()=='N':
print("se u later")

else:
again()

calculate()

Answer 1

Hi, can you make the code public so we can try it?

Answer 2

There are several ways, if go to your code and look for an option in the menu to switch from private to public

Answer 3

That's bcz you haven't added any condition for taking inputs a and b.
cut and paste your
a= int(input(..........
&
b= int(input(........
inside that if aman == "1": block.

And didn't get why are you recursively calling calculate().

Answer 4

bhai jab maine block likha toh error ho gaya...
explain me deeply I am very beginner.....thanks...

Answer 5

how's can I make it public ?