To print matrix using python

Question

you will be provided with the number of rows i.e. r and columns i.e. c as the input and your job is to create a matrix of size rxc.
Also, the matrix should have elements starting from 1 to rxc with an increment of one in row manner.

Example:

if r = 2 and c = 3
then the output is

1 2 3
4 5 6

Input Format:
Two numbers r and c in a single line separated by a space.

Output Format:
Elements of the generated matrix.
Each row should be printed in a new line with each element separated by a space.

Example:

Input:
3 4

Output:
1 2 3 4
5 6 7 8
9 10 11 12

input:
3 1

output:
1
2
3

Answer 1

here is the solution

r,c =input().split(" ")
r=int(r)
c=int(c)
mat=[[0 for i in range(c)]for j in range(r)]
val=1
for i in range(r):
for j in range(c):
mat[i][j]=val
val=val+1
for i in range(r):
for j in range(c):
if j !=(c-1):
print(mat[i][j],end=" ")
else:
print(mat[i][j],end="")
if i!=(r-1):
print()

Answer 2

def createMatrix(a,b):

matrix, q = [], 0

for _ in range(a):

auxrow = []

for _ in range(b):

q += 1

auxrow.append(q)

matrix.append(auxrow)

return matrix

This is done writing by rows, using an auxiliar row that its restarted when finishing each row. Then append it to final matrix.

q is the integer number increase.

Answer 3

tnx for your ans. but it isn't working. showing no output

Answer 4

tnx for your ans. but it isn't working. showing no output

Answer 5

You have to call the function and give it some arguments to use it. Add "print(createMatrix(3,4))" at the end of the script.

Dont put any indentation on this last statement, as it's not part of the function.

Answer 6

sorry it's didn't print the same pattern. It's printing as array.
But I have to print that as pattern

Answer 7

Just write the code
for i in range(row):
print(mat[row])

Works for square matrix
Here mat is a 2D matrix though