Explain me this code?

Question

public class practice
{
public static void main (String[] args)
{
int x = 10;
test(x);
}
static void test(int x)
{
System.out.println(x);
}
}

I dont understand this code plz explain...

Answer 1

It's easy :
1. Program execution starts from main method.
2. At test(x), the value of x goes as argument in test(x) method
3.Program jumps to test method definition
4.In method definition it prints the value of x which is 10 though System.out.println (x)

Answer 2

Complete the Java course. Everything you wrote is covered by the course.

Answer 3

no se nada de java pero con lo poco que se, te puedo decir que lo que hace es declarar una variable (x) al que le asigna el valor 10, luego llama a una función definida que lo que hace es pasar la variable x como argumento de la funcion y luego lo imprime, lo que da de salida 10.

Answer 4

Facu I don't understand your language. Explain in English.

Answer 5

I do not know anything about java but with what little I know, I can tell you that what you do is declare a variable (x) to which you assign the value 10, then call a defined function what it does is pass the variable x as argument of the function and then print it, what gives output 10. 🤦‍♂️