How it works?

Question

int a=10;
int *p1=&a;
int **p2=&p1;
cout<<**p2;

Output=10

Answer 1

Hi!
p1 is pointer to a=10, then p2 is pointer to p1.
System firstly searches for p1 address. Then it sees that p1 also keeps address, so it goes straight to the a. Output = 10.