for loop in java

Question

for(int x=0; x<=10; x=x+2) {
System.out.println(x);
}

how this condition of for loop print even number .I dont understand how x=x+2 print even number.

Answer 1

it works like this......

x will start at 0 so first it will print 0, then the x=x+2 statement will execute.
so x = 0 + 2.
now x is 2.
it will print 2 now.

and everytime x will be increased by 2 and always print even numbers only.

Answer 2

As x starts from zero which is an even no. Also if you even no. in an even no. the sum is even. Here in for loop you are adding 2 in zero then in 2 and so on till 10. So the outputs are even

Answer 3

x equals its current value of x then increment by 2 to its value;

x=0
x=0+2
x=2+2
x=4+2
x=6+2 ect ect

Answer 4

ok thanks, now its clear for me

Answer 5

here ,fill the blank with the with correct answer to form a loop x=0,____x<20___,____(x) x+=2

Answer 6

please I need help

Answer 7

it works like this......

x will start at 0 so first it will print 0, then the x=x+2 statement will execute.
so x = 0 + 2.
now x is 2.
it will print 2 now.

and everytime x will be increased by 2 and always print even numbers only.

Answer 8

it work like this.
since 1st value of x=0 and that is given x=x+2; so un this case x print 2 that is even and next value of x become 2 so next again print 4 which is even no like that ...it will always print even number.

Answer 9

thanks again Rajesh, I appreciate .

Answer 10

Very nice