XOR in python

Question

Its not how the XOR operator is done?
https://code.sololearn.com/cPOQua785Saq/?ref=app

Answer 1

You have to put paranthese around the expressions, like this:

(x==y) ^ (y==y)

Then you will have 0 or 1 (false or true), boolean/binary values.

Otherwise cases ⏩ Prometheus ⏪ mentioned will happen.

All values are stored in binary, the computer only knows binary.
We just have a representation in decimal, because we have 10 fingers and are used to it.

Like in decimal we can write it like this: 543 = 5*100 + 4 *10 + 3*1
we can also represent a number in binary:
6 = 0*8 + 1*4 + 1*2 + 0*1
so 6 is 0110 in binary

Answer 2

Just to let you know,
if a = 1 and b = 2,
a: 0 0 1
b: 0 1 0, then c = a^b will be:
c: (0^0) (0^1) (1^0), which is basically,
c: 0 1 1, or 3.

Answer 3

⏩ Prometheus ⏪ How fo u know how is the number in binnary?

Answer 4

What are you trying to do?

if x == x ^ y == y:
print("Both true")

x == x and y == y will be true (or 1) for any numbers x and y, but 1 ^ 1 will be 0, so it doesn't tell you that both expressions are true... Using a xor b to find out if a and b are both true or false isn't possible. a xor b is false if a and b are equal. But you still don't know if they're both true or both false. You could do something like if a and not (a^b) to find out if both a and b are true.