Problems with code

Question

#include <iostream>

struct Node{
int n = 0;
Node* next = nullptr;
Node* prev = nullptr;
};
void addNode(Node **n, Node **head, int x){
//problem starts from here
if(n){
*n->next = new Node;
*n->next->n = x;
*n->prev = *n;
*n = *n->next;
std::cout << *n->n << " " << *head->*next->n;
*n->next = nullptr;
}
else{
*n = new Node;
*head = *n;
*head->n = x;
*head->next = nullptr;
*head->prev = nullptr;
std::cout << *n->n << *head->n;
}
}

void printNode(Node *n){
if(n!=nullptr){
while(n->prev!=nullptr){
std::cout << n->n;
n = n->prev;
}
}
}

int main() {
Node *n = nullptr;
Node *head = nullptr;
addNode(&n, &head, 2);
addNode(&n, &head, 4);
printNode(head);
return 0;
}

If you don't understand what it does then ask, i will answer☺

Answer 1

What it supposed to do?
What it's doing?

[Edited]: It seems you are creating LL and adding nodes. And after that printing it.

Answer 2

Here's the code I made:
https://code.sololearn.com/cIGuM7oZos3J/?ref=app

Answer 3

Oleg Storm I am not much aware of pointer to pointer notation for passing and handling linked list.
You can remove the ampersand/dereference operator (you can use only single pointer) it will work fine.
You can check out these links for information:
¹https://stackoverflow.com/questions/3313233/linked-list-head-double-pointer-passing
²https://www.quora.com/Why-double-pointers-are-used-in-linked-list

Answer 4

nautaxh, yes it is a tipical node by me😆 and as you can see it always points to a nullptr, guys have already recommended me something but i gave up and want to aks for your help to complete the programme🙃

edit: it actually doesn't poit to nullptr now, so it is another problem(can be with **, as I'm new to it)

Answer 5

nautaxh, why haven't you used a pointer to pointer instead? Just curious🤔

Answer 6

to say the truth, i really enjoy learning from these forums