Is there a way to repeat a sequence of numbers for a set amount?

Question

For example,
list = [1,2,3,4,5]
I want to repeat the items in the list 7 times like so (1,2,3,4,5,1,2). Is this possible?

Answer 1

from itertools import cycle

def repeat(lst, times):
c = cycle(lst)
for i in range(times):
yield next(c)

print(*repeat([1,2,3,4,5], 7))

Answer 2

numbers = [1, 2, 3, 4, 5]

for i in range(7):
print (numbers[0])
numbers.append (numbers.pop(0))

Answer 3

from itertools import cycle
numbers = cycle([1, 2, 3, 4, 5])

for i in range(7):
print (next(numbers))

Answer 4

Jan Markus Well, that's how I understood the question.

How about this then?

a = [1,2,3,4,5]

n = 7
print((a * (n // len(a) + 1))[:n])
#[1,2,3,4,5,1,2]

Answer 5

list+list[:7-len(list)]?

Answer 6

What are you trying to do? The easiest way would be

a=[1,2,3,4,5]
print(7 * a)

You can also use also use this to iterate over the list:

for n in 7 * a:
print(n)