How to make a average program without using if statement?

Answer 1

You may need to elaborate on what you mean by an 'average' program.

Answer 2

Let's say you don't have a predetermined number of quizzes.

#include <iostream>
using namespace std;

int main (){

int quiz_num;

cout << "Please input the number of quizzes to be evaluated" << endl;
cin >> quiz_num;

int score[quiz_num];
int sum = 0;
int average;

for (int i = 0; i < quiz_num; i++)
{
cout << "Please input score for quiz " << i + 1 << endl;
cin >> score[i];
sum += score[i];
}

average = sum / quiz_num;

cout << "The average score is " << average << endl;

return 0;

}

My example displays the use of arrays. I hope it is comprehensible.

Answer 3

If you are saying to make a program of calculating average without if statement, then there is no need of if statement in it.

If you are saying that you want to create a program at an intermediate level, not an easy but average program 😅
then you can use ternary operator instead of if else statement.
eg.

#include <iostream>
using namespace std;

int main() {
/*Use ternary operator ?: instead of if. Both works same.*/
int i=2;
if(i%2==0)
cout<<1;
else
cout<<0;

/*above can also be written as*/

cout<<(i%2==0)?1:0;
return 0;
}

output is- 11

Answer 4

can you please make me a sample program ,
its my first time to learn c++, thank you.

Answer 5

#include <iostream>
using namespace std;
//this is comment
/* I'm gonna calculate the average of three numbers*/
int main(){
float num1,num2,num3,avg;
cout<<"please enter your three scores.";
cin>>num1;
cin>>num2;
cin>>num3;
avg=(num1+num2+num3)/3;
/*maybe you want it this way. an example:
avg=(num1*2+num2*4+num3*2)/(8);
*/
cout<<"the average of your scoresare:";
cout<<avg;
return 0;
}

you can add variables as many as you want and calculate their average.

Answer 6

computing average of quizes