Almost done

Question

def get_part(input):
if len(input) <= 1:
return input
num=int(input.split(input[-1],2)[0])
return num*input[-1]

def get_line(input):
parts=[]
for i in input.split(" "):
parts.append(get_part(i))
return "".join(parts)

n=input()
inputs=[]
inputs.append(n)
for input in inputs:
print(get_line(input))

if i
input : 4bab 18c 12g
outout : bbbbccccccccccccccccccgggggggggggg

how to make it output is
babbabbabbabccccccccccccccccccgggggggggggg

Answer 1

using regular expressions to get the number part from the string part.
if there is no number part or there is no text part, print the entry data.

^([1-9][0-9]*)([^1-9].*)$ means:
it starts with a digit between 1 and 9, following 0 or more digit between 0 and 9. that's the number part. the text part starts after a non digit character appears which may be followed anything.

import re

def get_part(input):
m = re.search('''^([1-9][0-9]*)([^1-9].*)#x27;'',input)
if m is not None:
return (int(m.group(1)),m.group(2))
return (1,input)

def get_line(input):
parts=[]
for i in input.split(" "):
(count,str)=get_part(i)
parts.append(str*count)
return " ".join(parts)

inputs=[]
inputs.append("4a 3c 9o 0")
inputs.append("11b 3keke 9")
inputs.append("2b0ss 3keke x")
inputs.append("l77t is 2n33t")

for input in inputs:
print(get_line(input))

-------output-------

aaaa ccc ooooooooo 0
bbbbbbbbbbb kekekekekeke 9
b0ssb0ss kekekekekeke x
l77t is n33tn33t