How the code actually work?

Question

cout << 4 + "sololearn";

Output:
learn

Answer 1

4+"sololearn" is like:
char str[] = "sololearn";
cout << str[4];

It starts outputing at the 'l' and goes until the '\0' after the 'n'.

Answer 2

John Wells Thanks for the explanation. it really helpfull...

Answer 3

John Wells btw, does cout << str[4] will only give an output 'l'

Answer 4

John Wells yup, that true..

Answer 5

My brain finally decided to work. I left out taking the address of to make it a string pointer instead of a character. This does the same output as your original:
char str[] = "sololearn";
cout << &str[4];

Answer 6

Xhy, I see.

I have done a bunch of C++ challenges but haven't encountered this one yet.

I am sure there's a lot of nice stuff!

Answer 7

Hm, interesting ...

Seems to be a shortcut for reading the string not from position 0 ('s') but position 4 ('l') (5 + the string would give 'earn').

Never seen it before ...

Answer 8

True... but you got the concept. str+4 wouldn't have made as much sense.

Answer 9

It's just another writing method.

Answer 10

HonFu If you do some challenges, you'll see quiz like this.

Answer 11

write code that display odd and even