Please explain this code,,i dont understand while(n!=0) loop

Question

Sum of its digits

#include <stdio.h>

int main()
{
int n, sum = 0, remainder;

printf("Enter an integer\n");
scanf("%d", &n);

while (n != 0)
{
remainder = n % 10;
sum = sum + remainder;
n = n / 10;
}

printf("Sum of digits is = %d\n", sum);

return 0;
}

Answer 1

n != 0 means the while loop will execute till the number not become 0 so it goes like this ex:-
n =123
So n != 0
Goes in loop
123%10=3
It goes in sum = 0+3 =3
Now
123/10=12
Now new number is n =12
Now 12 != 0 so
Goes in loop again
12%10=2
Sum =3+2=5
Then 12 / 10= 1
Now n=1
So 1 !=0
So 1%10= 1
Then
Sum = 5+1 =6
And 1/ 10 = 0 so
n=0
Now while loop condition is 0!=0 is false so loop stop and print the sum which is 6

Answer 2

Loop will work until 'n' is = 0. At end of every loop you divide 'n' by 10, so it will finally become 0.

Answer 3

thanks bro.... i understood... thank you