Casting

Question

Hi! I have an exercise in c++ where I have to transform a floating point to an integer, doing some changes and after that to change back the integer to float . I tried many ways to transform, the visual studio doesn't give error, but isn't transforming.
Ex:
Int a;
Float b=0;
B=b+a
Or
a=(float)a
I tried
The cast function as well

Answer 1

You are close when you specify a=(float)a; The problem here is you have cast an int to a float but are trying to store the result in an int.

Try:

#include <iostream>
using namespace std;

int main() {

int a = 0;
float b = 5.3f;
cout << "Before casting:" << endl << a << endl << b << endl;

//cast float to int
a = (int)b;
//cast int to float
b = (float)a;

cout << "After casting:" << endl << a << endl << b << endl;

return 0;
}

Answer 2

https://code.sololearn.com/cA6dhbRf5sZo/?ref=app

What results were you expecting and what are the input values?

Try copy and paste the following code into visual studio. Are the results the same?

Answer 3

It might be a compiler setting, it should/will give you a warning about loss of precision but it 'should' compile

Answer 4

Also please note that the following structure is a C-style way of doing the job

(target_type)variable_name or (target_type)immidiate value

In C++, there's an ugly form of conversion between two static types which was a deliberate design decision for making any sort of typecasting in the codebase distinguishable easily like so

static_cast<target_type>(variable_name)

It comes down to the fact that the good practice emphasizes minimizing all sort of typecasting (making the types consist by forcing the compiler to ignore the danger) throughout the program.

Answer 5

Olga Mohan
The best advice I can give you is to install a second IDE like Code::Blocks on your machine for days like today when you come up with some hiccups. Hopefully you're gonna find the issue pretty soon. Also don't forget to use F10 key and 'watch' feature for keeping track of the program flow.

Answer 6

This is what I have done and is not working in visual studio and I don't find the answer why. Sorry I wrote incorrect example

Answer 7

Thank you for your help , appreciate, but is not working. I definitely have a problem with some settings. :( But at list I know I am not wrong

Answer 8

Thank you!

Answer 9

You _declared_ a as int.
a will _always_ be int.
a = 19.666;
should result in 20.
You _cannot_ say
a = (float) a;
coz:
int a = 5.0; // For example
// a = 5 coz float is rounded
a = (float) a; // What you did
a = 5.0; // Result of what ya did
// a = 5 as per above explanation

Hope you _understand_ now. You returned float to an int in your example by doing a = (float) a; thus being like a = 1.0; which would yield a value of 1 for a.

Answer 10

Thank you!

Answer 11

I tried with static_cast and is the same result. There is a problem with settings or something?, doesn't give error but isn't transforming

Answer 12

Thanks I will try to find out :D

Answer 13

здравствуйте

Answer 14

тут кто-то может говорит на русском языке

Answer 15

Hello friends,I am not getting upcasting and downcasting can you explain please?