when we getting square root of 2 I use toFixed(3) but in this way sqrt(25)=5.000 /remove extra zeros. suggest improvements....

Question

https://code.sololearn.com/WPfOrY86m5xu/?ref=app

Answer 1

A trick I like is to use parseFloat/Number/+ in combination with toFixed:

parseFloat(Math.sqrt(i).toFixed(3))

OR,
Number(Math.sqrt(i).toFixed(3))

OR,
+(Math.sqrt(i).toFixed(3))

Answer 2

thanks it works

Answer 3

Glad I could help 😊