Print numbers 1 toN without using semicolon and loop ?

Question

#include<stdio.h>
#define N 10
int main(int num)
{
if(num<=N&&printf("%d",num)&&main(num+1))
}

Answer 1

I honestly don't know if it can be done without semicolons, but here's one with no loops in case it helps you:

#include <stdio.h>

#define N 10

int num=1;

int main() {
if (num<=N){
printf("%d ",num);
num++;
main();
}
return 0;
}