print all the numbers that do not exceed n the natural number and will give 1 balance when delivering each one on 2

Question

#include <iostream>
using namespace std;

int main()
{
int n, m, r=0;
cin>>n;
for (int k = 0; n>k; k++) {
m==k;}

while(m!=0){
if(m%2==1){
r++;
}
m/=2;
}

cout<<r<<endl;
return 0;
}
// I don't know where is my mistake

Answer 1

I dont really get what you are trying to achieve.. but there are some mistakes in the code syntax:
m==k should be in m = k maybe because with == you are not assaigning a value but comparing it!
Also the curly braces position is not good I do believe!
If you want to print all numbers you should put thr cout inside the while loop and the while loop inside the for loop!