How modouls operator work in while loop?

Question

In C++ Help to Explain these codes

https://code.sololearn.com/cbA49Y73EAuG/?ref=app
https://code.sololearn.com/c1L3w0xh1p45/?ref=app

Answer 1

* 1st code.

int x = 7;
while(x%3)//repeat while x % 3 is non zero
{
x += (x-2);// x is now 12 (7 + (5))
x /= 2;//x is now 6 (12 / 2)
}
// loop stops because 6 % 3 == 0
cout << x;// you get 6

* 2nd code.

int x = 25;
while(x%3)//repeat while x % 3 is non zero
{
x++;// x is incremented ...
// x = 26, loop repeats (26 % 3 = 2)
// x = 27, loop will stop (27 % 3 = 0)
}
cout << x;// you get 27

I think it goes like this : )

Answer 2

You have to declare a fixed condition like this code :-
(Corrected code of Quiz while)

https://code.sololearn.com/cy2oKYyPWXE3/?ref=app
https://code.sololearn.com/cMx23Dhl4ATQ/?ref=app

Answer 3

You not have the proper condition of (x % 3) so every value of x must be satisfied in while condition

Answer 4

They are not being multiplied! The sole responsibility of multi(x-1, y) is pushing the number 5 on the stack for 5 times as

x = 5, push 5
x = 4, push 5
x = 3, push 5
x = 2, push 5
x = 1, push 5
x = 0, beginning of the recursive addition as above.

On the paper you have
5 + 5 + 5 + 5 + 5 = 25

Answer 5

Ipang
Thanks

Answer 6

#include <iostream>
using namespace std;

int multi(int x, int y) {
int sum = 0;
if (x == 0)
return 0;
else
return multi(x - 1, y) + y;
}

int main() {
cout << multi(5, 5);
return 0;
}

/*
Stack status when x == 0

| 5 |
| 5 |
| 5 |
| 5 |
| 5 |

That is, the program has stored the value of `y` 5 times in the stack frame
Popping the stack's content from above yields

return 0 + 5 = 5
return 5 + 5 = 10
return 10 + 5 = 15
return 15 + 5 = 20
return 20 + 5 = 25

And as can be seen, the last return would return the correct result of the multiplication.
*/

Answer 7

The while condition returns remainder for division

If it is zero the while loop takes it as Boolean false
If it is nonzero it is taken as Boolean true

Answer 8

(x%3) is treated by the compiler to be the same as (x%3!=0)

Answer 9

OkBipin Tatkare - (B. R. T)

Answer 10

I understand how
While(x%3 != 0) &
while(x%3 == 1)
Works
But how
while(x%3)
Works

Answer 11

dheeraj
Bipin Tatkare - (B. R. T)
Thanks guys i understand how these codes work

Answer 12

OK I get it

Answer 13

But why the value inside the function
multi(x-1,y)
multiplying