Can someone explain this code?

Question

arr = [0, 1, 2, 3, 4, 5, 6]
i = 0
for _ in arr:
del arr[i]
i = i + 1
print(arr)

Why does this code print odd numbers?

Answer 1

First the list is [0, 1, 2, 3, 4, 5, 6].

In the first iteration, the first element (arr[0]) is deleted, which is 0. Now the list is [1, 2, 3, 4, 5, 6].

Then, from the updated (!) list, the second element is deleted, which is 2. Now the list is [1, 3, 4, 5, 6].

Then, the third element is deleted, which is 4 etc.

You'll end up with [1, 3, 5].

You can add

print('_:', _)
print('arr:', arr)

in the for loop to understand better what it does.

Answer 2

Thanks!

Answer 3

I don't get the whole of it but half of it, thank for this question SlavaLucker and answer Anna