How can I find position of one array in another (C) ?

Question

I have an array and I want to find what is position of another array in it .

Answer 1

strstr() will find the position of one string (char array) in another but not the position of one generic array in another.

Answer 2

I made code that make auto uppercasing and I want pepole to enter any other words that need to be uppercased in their text . For a now this code looks like that :
#include <stdio.h>
#include <stdlib.h>
int main() {
int j=-1;
char s [256];
do {j++;scanf("%c",&s[j]);}
while (s[j]!='\n');
s[0]=s[0]-32;
for (int i=0;s[i]!='\n';i++){
if (s[i]=='.'||s[i]=='\"'){i++;
if (s[i]==' ')i++;
else
s[i]=s[i]-32;}}
j=-1;
do {j++;printf("%c",s[j]);}
while (s[j]!='\n');
return 0;
}

Answer 3

I have found a method . Thanks everyone , who wanted to help . You can do it with the help of:
Pointer= strstr ( StringWhereToFind , StringToFind )(You'll need do include in your program string.h file)

Answer 4

Have you written a code? If yes, can you share it please, then I can help you.

Answer 5

So code should look like something like that ?

int /*(for example)*/ array1[10] , array2[5] , same=0 , position;
for (int i=0;i<sizeof(array1)/ sizeof(array1[0]);i++){
if (array1[i]==array2[i]){
for (int j=i;j<sizeof(array2)/ sizeof(array2[0]);j++){
if (array1[j]==array2[j])same++;
else same=0;
}
}if (same==sizeof(array2)/sizeof(array2[0]))position=i;
}

Is there any other , simplier way to do it?