PHP - why I can't get the variable $name ?

Question

Hello everyone :)

In the course "variable scope", there is this code (posted bellow) but I don't understand why the course say that $name is not accesible in the function if it's a global variable (this is exactly what the course say : "This script will produce an error, as the $name variable has a global scope, and is not accessible within the getName() function.")

Because if I right understand global variable, it's can be accesed from everywhere, not only in a specific function (?).

<?php
$name = 'David';
function getName() {
echo $name;
}
getName();

// Error: Undefined variable: name
?>

Answer 1

You can assign it into the global array

$GLOBALS["name"] = "David";

Or use global keyword inside the function before using it

$name = 'David';
function getName() {
global $name;
echo $name;
}

Answer 2

Thank's for you answer !

So, by default the function is "local" in a specific variable. But, if I precise "global" in front of $name I could access to it everywhere (even in my variable) ?

Answer 3

In function instead of calling as $name call as
$GLOBALS['name'];

Answer 4

it will be better if you use OOP programming

class User{
private $name;
public function setName($name){
$this->name = $name;
}
public function getName(){
return $this->name;
}
}

//using class
$user = new User;
$user->setName('David');
echo $user->getName();

Answer 5

thank you

Answer 6

To use a variable in PHP you put it as
$GLOBALS[“name”] = “David”;

Answer 7

Donald Faulknor $name in this example is a global variable. It's in the $GLOBALS array just as $_POST, $_SERVER, and the other superglobals are in the $GLOBALS array.

Take a look at this code to see this more clearly.

https://code.sololearn.com/wnj8d35bQJJM/?ref=app

Answer 8

$name has to be defined within the function to use it in the function. On another note $name is not a global variable. $_POST is an example of a global variable. You might be confusing global variable with prefefined variable or reserved keyword; however, $name is neither. $name is free to use however you want withing the rules of variables.

Answer 9

you most write:$this->getName();
and this variable defind $global

Answer 10

no,int bihaend