In mathematics,the factorial of an integer n,denoted by n! is the following product:n!=1*2*...*n

Question

For the given integer n calculate the value 1!+2!+3!+...+n!
Try to discover the solution that uses only one for-loop.And don't use math module in this exercise.
Ex input:
4
Ex output:
33
I can't do this!Could someone help me?

Answer 1

周志桓
Sorry friend, this is not Python solution,
but you can use the algorithm!

// A simple for-loop calculation
int n = 10;
int result = 1;

for (int i = 1; i <= n; ++i) {
result *= i;
}

print( result ); //Output: 3628800

• We simply loop from 1 to n, adding the respectful number to the product at each iteration.

Answer 2

Thanks Jay Matthews and Danijel lvanovic

Answer 3

You can use recursion

Answer 4

I use :for i in range...
But I don't know how to do it.

Answer 5

But it starts is:
a=int(input())
Ex input 5:
1!*2!*3!*4!*5!=153
Output is:
153