Why is 5 - 4.99 = 0.0100002289? [SOLVED]

Question

When subtracting two float numbers (cost and moneyPaid) the result is (according to the program) 0.0100002289 (also stored in a float). Why does this happen? You don't need a mathematician to figure out that it's wrong. Using other other values still led to similar results.

Relevant Code (very shortened, no user interaction):
using System;
namespace ChangeCalculator
{
class Program
{
static float cost = 4.99F;
static Coins input;
static float moneyPaid;
static float changeAmount;
static Coins changeCoins;

static void Main()
{
moneyPaid = 5.00F
changeAmount = moneyPaid - cost; //changeAmount = 0.0100002289
changeCoins = calculateChange(changeAmount);
displayReturn(changeCoins);
}
}
}

Answer 1

float are only accurate to 6 digits
so 4.99 is actually something b/w 4.990001 to 4.989999

Answer 2

https://www.sololearn.com/Discuss/72830/why-does-0-1-0-2-evaluate-to-0-30000000004

5.0 is accurate and precise:
http://www.binaryconvert.com/result_float.html?decimal=053046048

4.99 is 4.9899997711181640625E0...
http://www.binaryconvert.com/result_float.html?decimal=052046057057

Answer 3

I got 0.0100002 for c++ language which is right. Yours is a little different because of those static variables and methods.

Answer 4

Sorry, my fault. It's 5 - 4.99. However it's not 5.0000002289 - 4.9900000000.