Does pass by reference only use pointers and addresses ?

Question

void passbyRef(int *x);
int main{
int boy = 13;

passbyRef(&boy);
cout<<"boy is now "<<endl;

}

void passbyRef(int *x){
*x = 23;
}

Answer 1

You will have to modify your code a bit

#include <iostream>
using namespace std;

void passbyReference(int *x);

int main()
{
int boy = 13;
passbyReference(&boy);
cout << "boy is now " << boy;
return 0;
}

void passbyReference(int *x)
{
*x = 23;
}

What happens here is that the function accepts either a pointer, or an address as an argument, and the function will modify the values of the pointer which points to that address. In this example above, I passed the address of boy using &boy. You may also use a pointer to store address of boy and pass the pointer.

Answer 2

You may have to elaborate on your query, or provide an example code.

Answer 3

thank you very much