Doubt

Question

Hi friends, I really don’t understood why this code prints the 5...

a = [4,5,6,7]
Try:
print(a[True])
Except:
print(0)

Can somebody explain this program please? Tks!!

Answer 1

You can't really do `a[True]` because `True` is not a number. So python will convert `True` to a number, and `True` will become `1`. `False` becomes `0`.

This is called type coercion!

Answer 2

True & False are subset of integer set. True==1, False==0 so a[True] is a[1]

Answer 3

Maybe your keyboard did this or something but take note that the try and except must be in lowercase.

Answer 4

thanks a lot brother! it’s really cleary now!

Answer 5

This code prints 5 because a[True] is a[1]
The exception is not raised.