Python quiz - How does this work?

Question

a = [0, 1, 2, 3]
for a[-1] in a:
print(a[-1])

Output is 0, 1, 2, 2

How does this work?

Answer 1

The for loop iterates over the values of list "a" and assings them to a[-1].

# Initial value
a = [0, 1, 2, 3]

First iteration (a[0] == 0):
a[-1] = 0
# a = [0, 1, 2, 0]

Second iteration (a[1] == 1):
a[-1] = 1
# a = [0, 1, 2, 1]

Third iteration (a[2] == 2):
a[-1] = 2
# a = [0, 1, 2, 2]

Fourth iteration (a[3] == 2):
a[-1] = 2
# a = [0, 1, 2, 2].

Answer 2

To be honest I want to know the answer too. I have been puzzled by this quiz too

Answer 3

yves houedande Please ask your question on a separate post. And remember to use the search bar to avoid duplicates.
https://www.sololearn.com/discuss/1704704/?ref=app

Answer 4

code:
a = [0,1,2,3]
for a[0] in a:
print(a)

output:
[0, 1, 2, 3]
[1, 1, 2, 3]
[2, 1, 2, 3]
[3, 1, 2, 3]

code:
a = [0,1,2,3]
for a[1] in a:
print(a)

output:
[0, 0, 2, 3]
[0, 0, 2, 3]
[0, 2, 2, 3]
[0, 3, 2, 3]

'a' is global variable, but in the loop 'a' it's a local variable. the digits from the global array are passed to the second element of the local array. I remind you that the index -1 means the last element of the array. that's why

code:
a = [0,1,2,3]
for a[-1] in a:
print(a)

output:
[0, 1, 2, 0]
[0, 1, 2, 1]
[0, 1, 2, 2]
[0, 1, 2, 2]

'a' is an array in a loop, we can get any element of it, so

code:
a = [0,1,2,3]
for a[-1] in a:
print(a[-1])

output:
0
1
2
2

Answer 5

i'm a biginner and i learn english too,so please for my way of speaking
my question is :what is local and global variable

Answer 6

can someone explain it a bit more clearly??

Answer 7

What the result for this:
Object-Oriented Programming
Classes question 2?

Answer 8

by knowledge

Answer 9

0,1,1,2