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What will be output?
int *p,*q; p=(int *)1000; q=(int *)2000; printf("%d",(q-p));
4 Answers
+ 3
You're using int pointers to point to arbitrary memory locations 1000 and 2000. Their difference is 1000, which means that there is room for 250 integers between those two locations. That's the output. You're not calculating with integers but using pointer arithmetic. That's a good way to make your program crash (or worse) if you don't know what you're doing
+ 1
250 and what Jay said.
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I tried
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Give me output pls