What is going here?

Question

#include <iostream>
using namespace std;

int main() {
int num;
num = 5;
num = num++;
cout<<num;
return 0;
}
// Output -> 5
Why????

Answer 1

What's the prblm

Answer 2

num = num++ means that the value of num is set to 5. The ++ doesn't get executed because of the value set.

Answer 3

cout<<num++;

It instructs the code to first pass the variable to cout and then increase it's value

Note:- ++ is at last

cout<<++num;

It instructs the code to first increase and then pass it to cout
Note:- ++ is at first

Answer 4

// Please, use increment without using the assignment

Correction :
num++ |or| num += 1

Answer 5

Guys,I want to Know the logic behind this scenario...
⚡Prometheus ⚡ and // Zohir 🐍 .

Answer 6

Check out 2nd ans

Answer 7

See when we use num++ it increases the value of num by 1 later(as it is a suffix increment) .
There for num++ is still 5 and when u assign it again
Num=num++ the value 5 is stored which is not incremented again

Answer 8

~ swim ~ So is my ans not appropriate.

Answer 9

Num=num++ is a problem

Answer 10

Try
Num=num+1

Answer 11

i would suggest you to use a different variable to store the value after its incremented.so for example:
num2=num++;

Answer 12

hey sorry just checked the code and it seems that storing it in different var wont work.
here's the solution for your code:
#include<iostream.h>
using namespace std;
int main(){
int num;
num=5;
num++;
cour<<num;
return 0;
}
output:
6

Answer 13

Because num++ is using post increment, Which has lower priority than assignment operator.

Answer 14

Num++ first return a value the only it increment the value so the output does not get affect
If you use ++num it first increment the value then only return the value

Answer 15

num++ means the value of num is first assigned to something and then incremented. But here, you assigned num to num, so the increment is lost. try ++num instead (first increase num by 1 and then assign it to something)