Error in list

Question

This creates an error
--------------------------------------
names=["Mumma : ", "Pappa : ", "Khand : ", "Rajan : ", "Manu : "]

contacts=[72167, 00475, 78842, 43142, 71390]

for i in range(5):
print(names[i],end="")
print(contacts[i])
-------------------------------------------

But when 00475 is replaced with 20475 Or anything starting for some other numeric not 0, that doesn't creates an error

For example
----------------------
names=["Mumma : ", "Pappa : ", "Khand : ", "Rajan : ", "Manu : "]

contacts=[72167, 20475, 78842, 43142, 71390]

for i in range(5):
print(names[i],end="")
print(contacts[i])
------------------------------------------

Doesn't create an error

Answer 1

In Python, numbers which start with 0 are octal.

https://stackoverflow.com/questions/11620151/what-do-numbers-starting-with-0-mean-in-python

If you want to store contact numbers, store them as strings instead of numeric literals.

Answer 2

In Python 3.x, a leading zero signifies that the number is not decimal and that a letter is expected. 0b begins a binary number, 0o begins an octal number and 0x begins a hexadecimal number. Try using 0o475 and see what you get.
See http://www.java2s.com/Tutorials/Python/Data_Types/How_to_create_integer_in_Python_octal_binary_hexadecimal_and_long_integer.htm

By the way, when you do a "for i in range(5):" kind of loop, you don't need to increment i as well - that's overkill. Delete or comment out the increment line and you will see the code runs just the same :)

Answer 3

Hmmm thnxx

Answer 4

Can you please elaborate this,"In Python, numbers which start with 0 are octal.
"