please explain

Question

float f=0.1;
if(f==0.1)
cout<<"true";
else
cout<<"false";
the answer is false why?

Answer 1

Here some excellent examples..

https://stackoverflow.com/questions/8266878/why-floating-point-value-conditions-failed-in-if-condition

https://www.geeksforgeeks.org/comparison-float-value-c/

Answer 2

Welcome 😊.. Vishesh Saxena

Answer 3

You need to replace float with double. But it is still weird, because I would expect that float will work too.

Answer 4

0.//exploration

float f=0.1
>means f has 0.1 float value

if(f==0.1)
>if checking that f value is equal (==) to 0.1, its not because f= 0.1, here 0.1 is not declared as float, its directly declared as double literal so it is not equal

cout="false"

Answer 5

0.1 is of type double. Try this: if (f == (float) 0.1)

Answer 6

Jan Štěch Why? 0.1 will obviously be better approximated with better precision (and as such be different).

Answer 7

Scooby thanks for the link .

Answer 8

Vlad Serbu thanks that too fit in the answer