so this should print variable a up to the value x (wtever u enter) i dont know whats wrong it just prints a++ until it times out

Question

int main()
{ int x;
int a = 1; int b = 2; int c = 3;
cin >> x;
for(a < x;a++;){
cout << a << endl;
}
return 0;}

Answer 1

for(; a < x; a++)

Answer 2

this should be:
for(; a<x;a++)
ie
1) initialisation of counter ( absent in your case)
2)stop condition
3)increment

Answer 3

#include <iostream>
using namespace std;

int main()
{ int x;
int a = 1; int b = 2; int c = 3;
cin >> x;
for(;a <= x;a++){
cout << a << endl;
}
return 0;

}

Answer 4

the for loop must be changed !! it has
1-initialization 2-condition to stop 3-increment/decrement

Answer 5

I think you wanna the code to print the value of a (I.e 1) for x-times. if am right , modify

int main()
{ int x;
int a = 1; int b = 2; int c = 3,k=0;
cin >> x;
for(;k< x;k++;){
cout << a << endl;
}
return 0;}

and it will print 1 for x-times

Answer 6

declare int a,x;
and
try this loop
for(a=1;a<x;a++)