List 1[], List2[]?

Question

list 1 = []
list2 = []
for i in range(5)[::-1]:
list1.append(i)
for j in list1[::-2]:
list2.append(j+1)
print(list1[2])
Solution: 2

So confused. It says append, but does not say with what?

Answer 1

I see. Thanks TT.

BTW, what would "print(list2[2]) be?
"j in list1[::2]:
list2.append(j+1)"

-2 in range 5[::-1] would be 2 also, right?

Answer 2

Thanks TT!

I took your advice and played around with the code constructing abd deconstructing it. I left a special note for you at the end, and got the same code to print, in a loop, from 4 to 0 and from 0 to 4:). Another mistake I made was not recognizing that "append(i) was a command? like i still need someone to yell "go" or "commute" to queue me. LOL. Anyway, thanks for the help👍🏻

list_a = []
list_b = []
for all_nums in range(5)[::-1]:
list_a.append(all_nums)
for anums in range(10)[::1]:
list_b.append(anums)
print(list_a[0])
print(list_a[1])
print(list_a[2])
print(list_a[3])
print(list_a[4])

print(list_b[0])
print(list_b[1])
print(list_b[2])
print(list_b[3])
print(list_b[4])
print("Thanks TT!")