The error says 'non-default argument follows default argument'

Question

def f(x,y,z='spam',a):
print(z)
f(1,2,'hello',5)

Answer 1

Yes 'cause you can't have non-default args after defaults.

def(x,y,a, z='spam'):
print(z)

is the correct way.

Answer 2

From the error, I would assume that you should keep all parameters for your function with a default value at the end as to avoid raising the error again.

It should be something like this:
def f(x,y,a,z="spam"):
# Code

Answer 3

def f(x,y,a,z='spam'):
print(z)
f(1,2,5,'hello')

Answer 4

Thanks Vasiliy

Answer 5

Thanks M.Watney

Answer 6

Thanks Faisal