Please, Explain it...

Question

#include <stdio.h>
int main() {
char arr[] = {'A','B','C','D'};
char *p = arr;
*p++;
printf("%c %c",*++p,--*p);
return 0;
}

//Output is : C A
// How ?

Answer 1

I understand it as below :
https://code.sololearn.com/cVvhS38haZMn/#c

Answer 2

*p++ increases the pointer to arr[1] (++ is quicker than *).

I think the arguments in the printf statement are evaluated from right to left (but printed from left to right).

--*p decreases the B at arr[1] to A; arr[1] is given out.

Then the pointer is increased to arr[2] and the letter there given out.

Undefined behaviour, though?

Answer 3

HonFu ya may be you are right but still doubtful btw thanks for your help...

Answer 4

That kind of riddles are made up with the aim to confuse us, so don't worry about it. 😉

Answer 5

Prokopios Poulimenos yes i think you are right i compared the same thing in c++ using cout the result was different (output was C B)...
so it is probably the printf in which the variables are update after the statement execution instead of while statement is running...

Answer 6

😂🤣 oh thank you buddy... 😎😘