How many time will this loop run?

Question

For(char c; c<256; ++c) {}

Answer 1

How many times?
➡ Never
error 1:'For' undefined //use for
error 2: c is uninitialised //:)

Answer 2

Seb TheS
Good point ;)
Thanks for rectifying me!
In c and cpp also there are 4 storage classes:
1.auto /local
2.extern /global
3.static
4.register

In general any variable defined without declaring their storage class is a auto/local variable
The default value of the auto variable is a garbage value. .

For static and extern classes this value is 0 by default

For register class it's garbage.

The variable defined in loop is treated as local variable so I was expecting that it'll get garbage value but actually SL compiler is assigning value 0 to it not garbage :(

I'm confused at this point why value is 0. because I think it is a local variable... as we can't access it outside of loop
You can try :
for(int i; i<=10;i++)
cout<<i;

/*it prints numbers from 0 to 10 means compiler is assigning it 0 implicitly */
I'll try to ask the question in another thread :)

By the way thảo nguyễn answer is ➡ 256

because count is starting from 0 and according to loops condition it'll stop when c becomes 256

Answer 3

Run this code on IDe, u wil see best answers and it will make your concepts strong

Answer 4

🇮🇳Omkar🕉 Don't C++ give it a garbage value then? Instead of raising the error 2?

Answer 5

🇮🇳Omkar🕉 Did you mention the static storage class twice with a purpose? 3 and 5?

Answer 6

Have you tested it out?
The best way to learn programming is to test code out for youself.

Answer 7

Thank you guys for all the advice and very detailed answers. I met this question in a random challenge and the answer is "Infinitely", which confused me a lot!