What's wrong with this code?

Question

I know I need to feed an input for condition that's not entirely why this code is going wrong.
The output conveniently goes right with else work work.
I'm still learning so tried datetime.today().day to define "today" but that didn't seem to work either.
Why?

https://code.sololearn.com/cHUOM7dyK6OP/?ref=app

Answer 1

Akhil Padmanabhan
you should give a number to if statement not a string !

because: 22 != '22'

so... use:

if today == 22:

instead of:

if today == 22:

full code working:

from datetime import datetime

today = datetime.today().day

if today == 22:
print("Party!")
elif today == '24':
if condition == ("headache"):
print("I should have a cup of tea")
else:
print ("Call Debbie")
else:
print ("work work work work work work.. I love you Riri")

print (today )
#what's wrong with code? Please comment.

Answer 2

Akhil Padmanabhan

first try this code...

from datetime import datetime

today = datetime.today().day

if today == 22:
print("Party!")
elif today == 24:
if condition == ("headache"):
print("I should have a cup of tea")
else:
print ("Call Debbie")
else:
print ("work work work work work work.. I love you Riri")

#what's wrong with code? Please comment.

Answer 3

Akhil Padmanabhan

you can read a good tutorial for taking input here:

https://www.geeksforgeeks.org/taking-input-in-JUMP_LINK__&&__python__&&__JUMP_LINK/

or instead, read sololearn tutorial:
https://www.sololearn.com/learn/Python/2426/

I hope I was helpful

Answer 4

Akhil Padmanabhan you are welcome! :)

Answer 5

Alessio

Yo man that's working totally..

Now I want to assign an input for condition how do i do that?

from datetime import datetime

today = datetime.today().day

condition = input("Are you having a headache?" )

if today == 25:
print("Party!")
elif today == 22:
if condition == ("Yes"):
print("I should have a cup of tea")
else:
print ("Call Debbie")
else:
print ("work work work work work work.. I love you Riri")

Answer 6

Alessio

Hell yea.. Thank you so much!!