Why output of this code is 6??

Question

https://code.sololearn.com/cmeNSzMFE5S6/?ref=app

Answer 1

If you don't use curly brackets, it'll only execute one line of code; it's not like Python

int i = 3;
if (!i) /*i to boolean is true because its not 0, so it is false*/
i++; /*this wont execute*/
i++;/*this will*/
if (i == 3) /*this is false because i equals 4*/
i += 2; /*this wont execute*/
i += 2; /*this will*/
3 + 1 + 2 = 6

Answer 2

Airree
Thank you very much 😁😁

Answer 3

Because it lacks braces on the ifs.

Answer 4

Without {} brackets if control only one line.... your both condition is false...
If(not true)=false
i=3;
i++; //then i become 4;
Second condition false
i+=2;
//i become 6;
Finally your answer is 6 ;

Answer 5

Check out this code in Python - the output is 6.

i=3

if(i==False):
i+=1

if(i==3):
i+=2

i+=1

print("The output is - "+ str(i))

Answer 6

it's because you haven't given curly braces. I tried check this out👍
#include <stdio.h>

int main() {

int i=3;
if(!i){
i++;
i++;
printf("%d",i);
}
if(i==3){
i+=2;
i+=2;
printf("%d",i);
}
return 0;
}

Answer 7

write code
you miss to add curly braces
check it out
#include <stdio.h>

int main() {

int i=3;
if(!i){
i++;
i++;
printf("%d",i);
}
if(i==3){
i+=2;
i+=2;
printf("%d",i);
}
return 0;
}

Answer 8

Please check it once again .... It's showing 7