Shortcuting Many If else in one for loop...

Question

if(i==1||j==1||i==2*n-1||j==2*n-1)
printf("%d",n);
else if(i==2||j==2||i==2*n-2||j==2*n-2)
printf("%d",n-1);
else if (i==3||j==3||i==2*n-3||j==2*n-3)
printf("%d",n-2);
else if(i==4||j==4||i==2*n-4||j==2*n-4)
printf("%d",n-3);
.
.
.
.
.
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else if(i==k||j==k||i==2*n-k||j==2*n-k)
printf ("%d",n-k+1);

If k is very big number like 1000
How can I use for loop in it ?

Answer 1

When checking a <number>
printf("%d", n - <number>);

But when checking for <k>
printf("%d", n - k + 1);

Why is this difference?
Are you checking from 1 to <k>?
What is this big loop program about?

Answer 2

Yes I want to check 1 to 1000.

Answer 3

Actually I don't know anything about minimum function. So I can't implement in terms of minimum function and hence I used if else to try to implement it...

By the way when I used this if else pattern

If we write if else statement till k = 3
And I entered the value of N =3
It was working so I thought that If we make a loop for it and The loop depends on the variable k which is dependent on N than we can make the pattern without using any built in function....So I asked

Answer 4

Actually I want the program to implement who will take input as N

If N=3

The pattern will look like

33333
32223
32123
32223
33333

If Value of N is 5

Then the pattern shown will be

555555555
544444445
543333345
543222345
543212345
543222345
543333345
544444445
555555555

Where 1 < N <1000

Answer 5

Ohk It worked

Answer 6

Actually I forgot to write break statement that's why it was not working

Answer 7

Thank You So much for your valuable answer 😊