How the output of this code i.e value of x is 3 at the end of the program.

Question

Please someone explain it .
https://code.sololearn.com/cs980PfqcJHR/?ref=app

#include <stdio.h>
#define square(x)(x*x)
int main() {
int x,y=1;
x=square(1+y);
printf("%d\n",x);
return 0;
}

Answer 1

Because define just copy & pastes what was defined.

So it goes
square(1+y) = (1+y*1+y) = (1+2*y) = (1+2*1) = 3

I have explained it in more detail here:
https://code.sololearn.com/c80ech3GBNvc/?ref=app

Answer 2

Thank you so much
both of you