This code is not working.Can anyone help me? I have to count no. of vowels in the string

Question

s="rams cingulate services "
x=len(s)

count=0
a=0

while a<=x:
if s[a]=="a" or s[a]=="e" or s[a]=="i" or s[a]=="o" or s[a]=="u":

count=count+1
a=a+1
print("count",count)

Answer 1

a = a + 1 needs to be indented. Otherwise it's not in the loop and you're creating an infinite loop.

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Btw, a more "pythonic" way to get the same result would be:

count=0

for c in s:
if c in 'aeiou':
count += 1

Your code isn't wrong. But you're basically writing a C code with Python syntax

Answer 2

Replace a<=x by a<x.
Don't forget list index starts at 0... And ends at len(list) - 1.